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36k^2-84k-24=0
a = 36; b = -84; c = -24;
Δ = b2-4ac
Δ = -842-4·36·(-24)
Δ = 10512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10512}=\sqrt{144*73}=\sqrt{144}*\sqrt{73}=12\sqrt{73}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-12\sqrt{73}}{2*36}=\frac{84-12\sqrt{73}}{72} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+12\sqrt{73}}{2*36}=\frac{84+12\sqrt{73}}{72} $
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